mybatis in查詢條件過長的解決
方法1:分次查詢,將參數且分割成多個短的查詢后合并
代碼:
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int splitNum =( int ) Math.ceil( ( float ) ids.length/ 999 ); //切片數量 List<String> itemIdList = new ArrayList<>(Arrays.asList(ids)); List<List<String>> splitList = averageAssign(itemIdList, splitNum); for (List<String> list : splitList) { param.put( "itemIds" ,list); List<Map<Object, Object>> itemStatisticsList = iProcessExtMapper.getItemStatisticsList(param); result.addAll(itemStatisticsList); } |
將list分成N等分方法方法:
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public static <T> List<List<T>> averageAssign(List<T> source, int n){ List<List<T>> result= new ArrayList<List<T>>(); int remaider=source.size()%n; //(先計算出余數) int number=source.size()/n; //然后是商 int offset= 0 ; //偏移量 for ( int i= 0 ;i<n;i++){ List<T> value= null ; if (remaider> 0 ){ value=source.subList(i*number+offset, (i+ 1 )*number+offset+ 1 ); remaider--; offset++; } else { value=source.subList(i*number+offset, (i+ 1 )*number+offset); } result.add(value); } return result; } |
方法2:xml文件中編寫sql
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i.id in < foreach collection = "itemIds" index = "index" item = "item" open = "(" close = ")" > < if test = "index != 0" > < choose > < when test = "index % 1000 == 999" > ) OR ID IN( </ when > < otherwise >,</ otherwise > </ choose > </ if > #{item} </ foreach > |
sql邏輯:
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ID IN (ids[0],ids[1]+...+ids[998]) OR ID IN (ids[999],ids[1000],...ids[ max ]) |
mybatis大于1000的in查詢的解決
之前公司一位同事寫的方法:
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< select id = "getByDirIds" parameterType = "string" resultMap = "dirDocLinkMap" > SELECT < include refid = "columns" /> FROM KM_DIR_DOC_LINK T WHERE T.DIR_ID IN < foreach collection = "array" index = "index" open = "(" close = ")" item = "item" separator = "," > < if test = "(index % 1000) == 999" >NULL) OR T.DIR_ID IN (</ if >#{item} </ foreach > </ select > |
但是隨著數據量增加,發現大于2000這種方法會報錯;
論證如下
解決辦法
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< foreach collection = "array" item = "item" index = "index" open = "(" close = ")" separator = "," > < if test = "(index % 999) == 998" > NULL ) OR DOC.ID IN (</ if >#{item} </ foreach > |
以上為個人經驗,希望能給大家一個參考,也希望大家多多支持服務器之家。
原文鏈接:https://blog.csdn.net/Mr_ye931/article/details/106102695