前言：
hello，大家好，這篇文章博主來分享一下C++實(shí)現(xiàn)數(shù)據(jù)結(jié)構(gòu)中的順序表的代碼。希望對(duì)大家有所幫助。
在博主之前的文章中，已經(jīng)詳細(xì)地寫過順序表，讀者可以點(diǎn)擊查看C語言如何建立鏈表并實(shí)現(xiàn)增刪查改，在之前的文章中，是用C語言來實(shí)現(xiàn)的，這篇文章中，我們用C++來實(shí)現(xiàn)。
代碼
1.SeqList.h
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#ifndef SEQLIST_H#define SEQLIST_H#include<iostream>using namespace std;template<class T,int MAXSIZE>class SeqList{ T data[MAXSIZE]; int length;public: SeqList(); SeqList(T a[],int n); ~SeqList(); int ListLength(); T Get(int pos); int Locate(T item); void SeqPrint(); void Insert(int i, T item); T Delete(int i);};#endif |
2.SeqList.cpp
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#define _CRT_SECURE_NO_WARNINGS 1#include"SeqList.h"template<class T, int MAXSIZE>SeqList<T,MAXSIZE>::SeqList(){ length = 0;}template<class T, int MAXSIZE>SeqList<T, MAXSIZE>::SeqList(T a[], int n){ if (n < MAXSIZE) { length = n; for (int i = 0; i < n; i++) { data[i] = a[i]; } } else { cerr << "您的數(shù)據(jù)已經(jīng)超過范圍，系統(tǒng)無法繼續(xù)工作" << endl; exit(-1); }}template<class T, int MAXSIZE>SeqList<T, MAXSIZE>::~SeqList(){}template<class T, int MAXSIZE>int SeqList<T, MAXSIZE>::ListLength(){ return length;}template<class T, int MAXSIZE>T SeqList<T, MAXSIZE>::Get(int pos){ if (pos > length || pos < 0) { cerr << "您要查找的位置不存在，系統(tǒng)無法繼續(xù)為您服務(wù)" << endl; exit(-1); } else { return data[pos - 1]; }}template<class T, int MAXSIZE>int SeqList<T, MAXSIZE>::Locate(T item){ for (int i = 0; i < length; i++) { if (data[i] == item) return i + 1; } return -1;}template<class T, int MAXSIZE>void SeqList<T, MAXSIZE>::SeqPrint(){ for (int i = 0; i < length; i++) { cout << data[i] << " "; } cout << endl;}template<class T, int MAXSIZE>void SeqList<T, MAXSIZE>::Insert(int i, T item){ if (length < MAXSIZE) { for (int j = length - 1; j>=i - 1; j--) { data[j + 1] = data[j]; } data[i - 1] = item; length++; } else { cerr << "抱歉，當(dāng)前已經(jīng)達(dá)到系統(tǒng)最大的儲(chǔ)存，無法為您插入" << endl; exit(-1); }}template<class T, int MAXSIZE>T SeqList<T, MAXSIZE>::Delete(int i){ if (length == 0) { cerr << "當(dāng)前無可刪除元素" << endl; exit(-1); } if (i<1 || i>length) { cerr << "該位置非法" << endl; exit(-1); } T x = data[i - 1]; for (int j = i; j < length; j++) { data[j - 1] = data[j]; } length--; return x;} |
3.test.cpp
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#define _CRT_SECURE_NO_WARNINGS 1#include"SeqList.cpp"#include<iostream>using namespace std;void menu(){ cout << "|------------------------------------|" << endl; cout << "|----------- 歡迎來到順序表 ---------|" << endl; cout << "|---------------1.插入---------------|" << endl; cout << "|---------------2.刪除---------------|" << endl; cout << "|---------------3.求長---------------|" << endl; cout << "|---------------4.取值---------------|" << endl; cout << "|---------------5.定位---------------|" << endl; cout << "|---------------6.打印---------------|" << endl; cout << "|---------------0.退出---------------|" << endl; cout << "|------------------------------------|" << endl;}int main(){ int *a; int n; cout << "請(qǐng)輸入您要構(gòu)造的順序表的長度" << endl; cin >> n; a = new int[n]; cout << "請(qǐng)輸入該順序表中的每一個(gè)元素" << endl; for (int i = 0; i < n; i++) { cin >> a[i]; } SeqList<int, 20>seq(a, n); cout << "現(xiàn)在開始我們的程序之旅" << endl; int input=0; do { menu(); cout << "輸入您要進(jìn)行的操作的編號(hào)" << endl; cin >> input; switch (input) { case 1: cout << "請(qǐng)輸入您要插入的位置和數(shù)值" << endl; int pos; int value; cin >> pos; cin >> value; seq.Insert(pos,value); break; case 2: cout << "請(qǐng)輸入您要?jiǎng)h除的位置" << endl; int pos1; cin >> pos1; cout << "您刪除的元素的值為："; cout << seq.Delete(pos1) << endl; break; case 3: cout << "您的順序表當(dāng)前的長度為：" << seq.ListLength() << endl; break; case 4: cout << "請(qǐng)輸入您要查找的位置" << endl; int pos2; cin >> pos2; cout << "您查找的元素的值為："; cout << seq.Get(pos2) << endl;; break; case 5: cout << "請(qǐng)輸入您要查找的元素" << endl; int item; cin >> item; cout << "您查找的元素的位置為："; cout << seq.Locate(item) << endl;; break; case 6: cout << "當(dāng)前順序表如下：" << endl; seq.SeqPrint(); break; case 0: cout << "程序退出，感謝使用" << endl; exit(-1); break; default : cout << "您的輸入有誤，請(qǐng)重新選擇" << endl; } } while (input); return 0;} |
總結(jié)
本篇文章就到這里了，希望能夠給你帶來幫助，也希望您能夠多多關(guān)注服務(wù)器之家的更多內(nèi)容!
原文鏈接：https://blog.csdn.net/weixin_53472920/article/details/121341808
